Codeforces Round #381 (Div. 1), problem: (C) Alyona and towers Solution C/C++

Hi guys , I just solved the third problem of round 381 , Hope you like it , feel free to comment any better solution .

#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define fi first
#define se second
typedef long long ll;
typedef long double ld;
const int inf=1e9+99;

const int N=1<<19;
struct dat {
ll d;
int ans;
int dL,dR;
int lenL,lenR,len;

void inc(ll dd) {
d += dd;
dL=dR=(d>0)-(d<0);
lenL=lenR=ans=!!d;
len=1;
}
void merge(const dat &L,const dat &R) {
ans=max(L.ans,R.ans);
dL=L.dL;
dR=R.dR;
len=L.len+R.len;
lenL=L.lenL;
lenR=R.lenR;
if(L.dR >= R.dL && L.dR && R.dL) {
ans=max(ans,L.lenR+R.lenL);
if(lenL==L.len) lenL += R.lenL;
if(lenR==R.len) lenR += L.lenR;
}
}
} rmq[N+N];

void inc(int x,ll d) {
x+=N;
rmq[x].inc(d);
for(;x>>=1;) rmq[x].merge(rmq[x+x],rmq[x+x+1]);
}

int main() {
int n; scanf(“%d”,&n);
int pr=-1;
for(int i=1;i<=n;i++) {
int a;
scanf(“%d”,&a);
if(i>1) inc(i-1,a-pr);
pr=a;
}

int m; scanf(“%d”,&m); for(;m–;) {
int l,r,d; scanf(“%d%d%d”,&l,&r,&d);
if(l>1) inc(l-1,d);
if(r<n) inc(r,-d);
printf(“%d\n”,rmq[1].ans+1);
}
}

(Visited 133 times, 1 visits today)
By |2017-04-07T22:11:49+00:00November 27th, 2016|Categories: C/C++, Programming||0 Comments