Programming

#include<cstdio> #include<cstring> #include<algorithm> #include<set> using namespace std; int n,k; struct node { int maxx,minn,sz; node() { int x;sz = 1; for(int i = 1; i <= k ; i...

#include <stdio.h> struct node { __int64 ans,num; }s; int main() { int n,k,m; while(~scanf("%d%d%d",&n,&k,&m)) { scanf("%I64d",&s.num); s.ans=1; int len=1; for(int i=1;i<n;i++) { int x; scanf("%d",&x); if(x==s.num) { s.ans++; if(s.ans==k) { s.ans=0; len--; } } else { s.num=x; s.ans=1; len++; } } int l=0,r=len-1; __int64 sum=0; while(s.num==s.num&&r>l) { if((s.ans+s.ans)>=k)sum+=k; s.ans=(s.ans+s.ans)%k; s.ans=0; if(s.ans!=0) { break; } l++,r--; } if(l==r) { if((s.ans*m)%k==0)sum=0; else sum+=((s.ans*m)%k); } else { for(int i=l;i<=r;i++) { sum+=(s.ans*m); } } printf("%I64dn",sum); } return 0; }

#include <iostream> using namespace std; const int maxn = 5e5; int n, x, a = 0, b = 1023, y; char...

#include<bits/stdc++.h> #define maxn 1000050 using namespace std; int a,b,c,n,k,m,t; int main() { scanf("%d%d",&n,&k); for (int i=0;i<n;i++) ...

#include<iostream> #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<algorithm> #include<cstdlib> #define eps 1e-7 using namespace std; double x,y,r,L; struct node{double l,r;}a; struct P{double x,y;}A,B,M,s,O,p; int n; inline double dis(P a,P b){return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));} inline P...

#include <cstdio> #include <algorithm> using namespace std; long long n,a,b,c,d,st,len,t; int q; int main() { scanf("%lld%lld%lld%lld%lld%lld%lld",&n,&a,&b,&c,&d,&st,&len); for (int i=1;i<=n;i++) scanf("%lld%d",&t,&q); t=-1; int now=1; long long change_rating=0,Min=0,rating=st; for (int i=1;i<=n;i++) { while...

#include <bits/stdc++.h> using namespace std; const int R = { {12, 13, 4, 5, 16, 17, 20, 21}, {14, 15, 6,...

#include<stdio.h> int main() { int n,i,j,k,m,A,B; scanf("%d",&n); for(i=1;i<=n;i++){ for(j=1;j<=6;j++){ scanf("%d",&A);} } for(i=1;i<=100;i++){ B=0;} for(i=1;i<=n;i++){ for(j=1;j<=6;j++){ B]=1; for(k=1;k<=n;k++){ for(m=1;m<=6;m++){ if (k!=i){ B*10+A]=1; } } } } } i=1; while(B){ i++;} printf("%d",i-1); return 0; }