Accepted Solution in C/C++ Archive

#include<bits/stdc++.h> #define ll long long ll multmod(ll a, ll b, ll moder){ a = (a % moder + moder) % moder, b = (b % moder + moder) % moder; ll ret = 0; for …

#include <stdio.h> #include <string.h> #include <stdlib.h> #define M 1000000007 int add(int a, int b) { return (a + b) % M; } int mult(int a, int b) { return ((long long) a * b) % …