Codeforces Round #393 (Div. 2) (8VC Venture Cup 2017 – Final Round Div. 2 Edition), problem: (F) Bacterial Melee Solution in C/C++

#include <bits/stdc++.h>
using namespace std;

const int mod = 1e9+7;

long long t[20000];

long long binpow(long long a, long long n){
long long ans = 1;
while(n){
if(n&1) ans = ans*a % mod;
a = a*a % mod;
n >>= 1;
}
return ans;
}

long long inv(long long x){
return binpow(x, mod-2);
}

long long c_n_k(long long n, long long k){
return t[n]*inv(t[k]) % mod * inv(t[n-k]) % mod;
}

const long long maxn = 5005, k = 26;

long long dp[maxn][maxn];

long long cnt[maxn];

long long p[maxn][k];

int main(){

t[0] = 1;
for(long long i = 1; i < 20000; i++)
t[i] = i*t[i-1] % mod;

long long n;
cin >> n;

string s;
cin >> s;

for(long long i = 0; i < k; i++)
p[n][i] = n;

for(long long i = n-1; i >= 0; i–){
memcpy(p[i], p[i+1], sizeof(p[i]));
p[i][s[i]-‘a’] = i;
}

for(long long i = 0; i < 26; i++)
dp[p[0][i]][1] = 1;

for(long long i = 0; i < n; i++){
p[i][s[i]-‘a’] = n;
for(long long l = 1; l <= n; l++){
dp[i][l] %= mod;
if(dp[i][l] == 0) continue;
for(long long j = 0; j < k; j++)
dp[p[i][j]][l+1] += dp[i][l];
cnt[l] = (cnt[l] + dp[i][l]) % mod;
}
}

long long ans = 0;

for(long long l = 1; l <= n; l++){
long long r = n-l;
ans = (ans + cnt[l]*c_n_k(r+l-1, r)) % mod;
}

cout << ans;

return 0;
}

#include <bits/stdc++.h>
using namespace std;

const int mod = 1e9+7;

long long t[20000];

long long binpow(long long a, long long n){
long long ans = 1;
while(n){
if(n&1) ans = ans*a % mod;
a = a*a % mod;
n >>= 1;
}
return ans;
}

long long inv(long long x){
return binpow(x, mod-2);
}

long long c_n_k(long long n, long long k){
return t[n]*inv(t[k]) % mod * inv(t[n-k]) % mod;
}

const long long maxn = 5005, k = 26;

long long dp[maxn][maxn];

long long cnt[maxn];

long long p[maxn][k];

int main(){

t[0] = 1;
for(long long i = 1; i < 20000; i++)
t[i] = i*t[i-1] % mod;

long long n;
cin >> n;

string s;
cin >> s;

for(long long i = 0; i < k; i++)
p[n][i] = n;

for(long long i = n-1; i >= 0; i–){
memcpy(p[i], p[i+1], sizeof(p[i]));
p[i][s[i]-‘a’] = i;
}

for(long long i = 0; i < 26; i++)
dp[p[0][i]][1] = 1;

for(long long i = 0; i < n; i++){
p[i][s[i]-‘a’] = n;
for(long long l = 1; l <= n; l++){
dp[i][l] %= mod;
if(dp[i][l] == 0) continue;
for(long long j = 0; j < k; j++)
dp[p[i][j]][l+1] += dp[i][l];
cnt[l] = (cnt[l] + dp[i][l]) % mod;
}
}

long long ans = 0;

for(long long l = 1; l <= n; l++){
long long r = n-l;
ans = (ans + cnt[l]*c_n_k(r+l-1, r)) % mod;
}

cout << ans;

return 0;
}

More from author

LEAVE A REPLY

Please enter your comment!
Please enter your name here

Related posts

Advertismentspot_img

Latest posts

Stop Buying Cheap Alternatives This Wireless Earbuds Accessories Is the Real Deal

📢 As an Amazon Associate, I earn from qualifying purchases.I stumbled across this while desperately trying to fix a recurring problem in my routine....

Where the OKC Thunder Rank Among the Top 10 NBA Teams Entering August

As the offseason progresses into August, the NBA landscape continues to undergo dramatic transformations. Major headline-grabbing moves, including LeBron James making his historic transition...

Stop Buying Cheap Alternatives This Portable Blender Bottle Is the Real Deal

📢 As an Amazon Associate, I earn from qualifying purchases.There comes a point when you realise that tolerating a frustrating situation is costing you...

Want to stay up to date with the latest news?

We would love to hear from you! Please fill in your details and we will stay in touch. It's that simple!