Codeforces Round #429 (Div. 1), problem: (E) In a Trap Solution In Java

import java.io.*;
import java.util.*;

public class E {

int[] a;

static final int LOG = 8;
static final int BLOCK = 1 << LOG;
static final int LOW_MASK = BLOCK – 1;

int[] head;
int[] next;
int[] to;

int[] par;
int[] depth;

void dfs(int v, int p) {
par[v] = p;
for (int e = head[v]; e >= 0; e = next[e]) {
int u = to[e];
if (u == p) {
continue;
}
depth[u] = depth[v] + 1;
dfs(u, v);
}
}

int[][] go = new int[2][BLOCK * LOG + 1];
int triePtr = 0;

int newNode() {
go[0][triePtr] = go[1][triePtr] = -1;
return triePtr++;
}

void submit() {
int n = nextInt();
int q = nextInt();

a = new int[n];
for (int i = 0; i < n; i++) {
a[i] = nextInt();
}

head = new int[n];
next = new int[2 * n – 2];
to = new int[2 * n – 2];
Arrays.fill(head, -1);

for (int i = 0; i < n – 1; i++) {
int v = nextInt() – 1;
int u = nextInt() – 1;

to[2 * i] = u;
next[2 * i] = head[v];
head[v] = 2 * i;

to[2 * i + 1] = v;
next[2 * i + 1] = head[u];
head[u] = 2 * i + 1;
}

par = new int[n];
depth = new int[n];
dfs(0, -1);

int[] parBlock = new int[n];

int[][] prec = new int[n][];

for (int i = 0; i < n; i++) {
if (depth[i] < BLOCK) {
continue;
}
int[] bestLow = new int[BLOCK];
Arrays.fill(bestLow, -1);

int v = i;
for (int j = 0; j < BLOCK; j++) {
int now = a[v] ^ j;
int low = now & LOW_MASK;
int high = now >> LOG;
bestLow[high] = Math.max(bestLow[high], low);
v = par[v];
}

parBlock[i] = v;

triePtr = 0;
int root = newNode();

for (int j = 0; j < BLOCK; j++) {
if (bestLow[j] == -1) {
continue;
}

v = root;

for (int k = LOG – 1; k >= 0; k–) {
int bit = getBit(j, k);
if (go[bit][v] == -1) {
go[bit][v] = newNode();
}
v = go[bit][v];
}
}

prec[i] = new int[BLOCK];

for (int j = 0; j < BLOCK; j++) {
v = root;

int highPicked = 0;

for (int k = LOG – 1; k >= 0; k–) {
int bit = getBit(j, k);
if (go[bit ^ 1][v] != -1) {
highPicked |= (bit ^ 1) << k;
v = go[bit ^ 1][v];
} else {
highPicked |= bit << k;
v = go[bit][v];
}
}

prec[i][j] = ((highPicked ^ j) << LOG) | bestLow[highPicked];
}

}

while (q– > 0) {
int top = nextInt() – 1;
int btm = nextInt() – 1;

int ret = 0;
int i = 0;
for (;; i++) {
if (depth[btm] – BLOCK >= depth[top]) {
ret = Math.max(ret, prec[btm][i]);
btm = parBlock[btm];
} else {
break;
}
}

i <<= LOG;
while (btm != -1 && depth[btm] >= depth[top]) {
ret = Math.max(ret, a[btm] ^ i);
btm = par[btm];
i++;
}

out.println(ret);
}
}

int getBit(int mask, int i) {
return (mask >> i) & 1;
}

void preCalc() {

}

void stress() {

}

void test() {

}

E() throws IOException {
br = new BufferedReader(new InputStreamReader(System.in));
out = new PrintWriter(System.out);
preCalc();
submit();
// stress();
// test();
out.close();
}

static final Random rng = new Random();

static int rand(int l, int r) {
return l + rng.nextInt(r – l + 1);
}

public static void main(String[] args) throws IOException {
new E();
}

BufferedReader br;
PrintWriter out;
StringTokenizer st;

String nextToken() {
while (st == null || !st.hasMoreTokens()) {
try {
st = new StringTokenizer(br.readLine());
} catch (IOException e) {
throw new RuntimeException(e);
}
}
return st.nextToken();
}

String nextString() {
try {
return br.readLine();
} catch (IOException e) {
throw new RuntimeException(e);
}
}

int nextInt() {
return Integer.parseInt(nextToken());
}

long nextLong() {
return Long.parseLong(nextToken());
}

double nextDouble() {
return Double.parseDouble(nextToken());
}
}

Knicks, NYC Officials Spar...

A heated political and sports dispute has erupted in...

curl-programming-lang 1.0.2

Introduction to curl-programming-lang 1.0.2 The open-source developer ecosystem continues to...

Why Everyone is Obsessed with the Smart Plug Wifi Outlet

Are you tired of dealing with everyday frustrations that slow down your routine? We've all been...

Knicks, NYC Officials Spar Over MSG Watch Parties

A heated political and sports dispute has erupted in New York City, as Madison Square Garden (MSG) Entertainment and local public officials trade sharp...

Why Everyone is Obsessed with the Under Desk Foot Rest

Are you tired of dealing with everyday frustrations that slow down your routine? We've all been...

Why Everyone is Obsessed with the Rug Gripper Pads

Are you tired of dealing with everyday frustrations that slow down your routine? We've all been...

curl-programming-lang 1.0.2

Introduction to curl-programming-lang 1.0.2 The open-source developer ecosystem continues to thrive with the introduction of innovative tools designed to simplify software creation. A fascinating new...

Why Everyone is Obsessed with the Blind Spot Mirrors

Are you tired of dealing with everyday frustrations that slow down your routine? We've all been...

Why Everyone is Obsessed with the Magnetic Spice Rack

Are you tired of dealing with everyday frustrations that slow down your routine? We've all been...

Why Everyone is Obsessed with the Webcam Cover Slide

Are you tired of dealing with everyday frustrations that slow down your routine? We've all been...

Why Everyone is Obsessed with the Magnetic Cabinet Locks

Are you tired of dealing with everyday frustrations that slow down your routine? We've all been...