Codeforces Round #443 (Div. 2), problem: (D) Teams Formation Solution In C/C++

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#include <stdio.h>
struct node
{
__int64 ans,num;
}s[101000];
int main()
{
int n,k,m;
while(~scanf(“%d%d%d”,&n,&k,&m))
{
scanf(“%I64d”,&s[0].num);
s[0].ans=1;
int len=1;
for(int i=1;i<n;i++)
{
int x;
scanf(“%d”,&x);
if(x==s[len-1].num)
{
s[len-1].ans++;
if(s[len-1].ans==k)
{
s[len-1].ans=0;
len–;
}
}
else
{
s[len].num=x;
s[len].ans=1;
len++;
}
}
int l=0,r=len-1;
__int64 sum=0;
while(s[l].num==s[r].num&&r>l)
{
if((s[l].ans+s[r].ans)>=k)sum+=k;
s[l].ans=(s[l].ans+s[r].ans)%k;
s[r].ans=0;
if(s[l].ans!=0)
{
break;
}
l++,r–;
}
if(l==r)
{
if((s[l].ans*m)%k==0)sum=0;
else sum+=((s[l].ans*m)%k);
}
else
{
for(int i=l;i<=r;i++)
{
sum+=(s[i].ans*m);
}
}

printf(“%I64d\n”,sum);
}
return 0;
}

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Affiliate Disclosure: This post contains Amazon affiliate links. If you purchase through these links, eBlogarithm may earn a commission at no extra cost to you. Prices and availability are subject to change.

#include <stdio.h>
struct node
{
__int64 ans,num;
}s[101000];
int main()
{
int n,k,m;
while(~scanf(“%d%d%d”,&n,&k,&m))
{
scanf(“%I64d”,&s[0].num);
s[0].ans=1;
int len=1;
for(int i=1;i<n;i++)
{
int x;
scanf(“%d”,&x);
if(x==s[len-1].num)
{
s[len-1].ans++;
if(s[len-1].ans==k)
{
s[len-1].ans=0;
len–;
}
}
else
{
s[len].num=x;
s[len].ans=1;
len++;
}
}
int l=0,r=len-1;
__int64 sum=0;
while(s[l].num==s[r].num&&r>l)
{
if((s[l].ans+s[r].ans)>=k)sum+=k;
s[l].ans=(s[l].ans+s[r].ans)%k;
s[r].ans=0;
if(s[l].ans!=0)
{
break;
}
l++,r–;
}
if(l==r)
{
if((s[l].ans*m)%k==0)sum=0;
else sum+=((s[l].ans*m)%k);
}
else
{
for(int i=l;i<=r;i++)
{
sum+=(s[i].ans*m);
}
}

printf(“%I64d\n”,sum);
}
return 0;
}

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As an Amazon Associate, eBlogarithm earns from qualifying purchases. Prices and availability are subject to change.

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